Optimal. Leaf size=133 \[ -\frac {2 a^2 \sqrt {c+d x^n}}{b^2 n (b c-a d) \sqrt {a+b x^n}}-\frac {(3 a d+b c) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x^n}}{\sqrt {b} \sqrt {c+d x^n}}\right )}{b^{5/2} d^{3/2} n}+\frac {\sqrt {a+b x^n} \sqrt {c+d x^n}}{b^2 d n} \]
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Rubi [A] time = 0.16, antiderivative size = 133, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {446, 89, 80, 63, 217, 206} \begin {gather*} -\frac {2 a^2 \sqrt {c+d x^n}}{b^2 n (b c-a d) \sqrt {a+b x^n}}-\frac {(3 a d+b c) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x^n}}{\sqrt {b} \sqrt {c+d x^n}}\right )}{b^{5/2} d^{3/2} n}+\frac {\sqrt {a+b x^n} \sqrt {c+d x^n}}{b^2 d n} \end {gather*}
Antiderivative was successfully verified.
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Rule 63
Rule 80
Rule 89
Rule 206
Rule 217
Rule 446
Rubi steps
\begin {align*} \int \frac {x^{-1+3 n}}{\left (a+b x^n\right )^{3/2} \sqrt {c+d x^n}} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {x^2}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx,x,x^n\right )}{n}\\ &=-\frac {2 a^2 \sqrt {c+d x^n}}{b^2 (b c-a d) n \sqrt {a+b x^n}}+\frac {2 \operatorname {Subst}\left (\int \frac {-\frac {1}{2} a (b c-a d)+\frac {1}{2} b (b c-a d) x}{\sqrt {a+b x} \sqrt {c+d x}} \, dx,x,x^n\right )}{b^2 (b c-a d) n}\\ &=-\frac {2 a^2 \sqrt {c+d x^n}}{b^2 (b c-a d) n \sqrt {a+b x^n}}+\frac {\sqrt {a+b x^n} \sqrt {c+d x^n}}{b^2 d n}-\frac {(b c+3 a d) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx,x,x^n\right )}{2 b^2 d n}\\ &=-\frac {2 a^2 \sqrt {c+d x^n}}{b^2 (b c-a d) n \sqrt {a+b x^n}}+\frac {\sqrt {a+b x^n} \sqrt {c+d x^n}}{b^2 d n}-\frac {(b c+3 a d) \operatorname {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b x^n}\right )}{b^3 d n}\\ &=-\frac {2 a^2 \sqrt {c+d x^n}}{b^2 (b c-a d) n \sqrt {a+b x^n}}+\frac {\sqrt {a+b x^n} \sqrt {c+d x^n}}{b^2 d n}-\frac {(b c+3 a d) \operatorname {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b x^n}}{\sqrt {c+d x^n}}\right )}{b^3 d n}\\ &=-\frac {2 a^2 \sqrt {c+d x^n}}{b^2 (b c-a d) n \sqrt {a+b x^n}}+\frac {\sqrt {a+b x^n} \sqrt {c+d x^n}}{b^2 d n}-\frac {(b c+3 a d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x^n}}{\sqrt {b} \sqrt {c+d x^n}}\right )}{b^{5/2} d^{3/2} n}\\ \end {align*}
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Mathematica [A] time = 0.52, size = 185, normalized size = 1.39 \begin {gather*} \frac {\sqrt {b c-a d} \left (-3 a^2 d^2+2 a b c d+b^2 c^2\right ) \sqrt {a+b x^n} \sqrt {\frac {b \left (c+d x^n\right )}{b c-a d}} \sinh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x^n}}{\sqrt {b c-a d}}\right )-b \sqrt {d} \left (c+d x^n\right ) \left (-3 a^2 d+a b \left (c-d x^n\right )+b^2 c x^n\right )}{b^3 d^{3/2} n (a d-b c) \sqrt {a+b x^n} \sqrt {c+d x^n}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.31, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{-1+3 n}}{\left (a+b x^n\right )^{3/2} \sqrt {c+d x^n}} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [B] time = 0.57, size = 540, normalized size = 4.06 \begin {gather*} \left [\frac {4 \, {\left (a b^{2} c d - 3 \, a^{2} b d^{2} + {\left (b^{3} c d - a b^{2} d^{2}\right )} x^{n}\right )} \sqrt {b x^{n} + a} \sqrt {d x^{n} + c} + {\left ({\left (b^{3} c^{2} + 2 \, a b^{2} c d - 3 \, a^{2} b d^{2}\right )} \sqrt {b d} x^{n} + {\left (a b^{2} c^{2} + 2 \, a^{2} b c d - 3 \, a^{3} d^{2}\right )} \sqrt {b d}\right )} \log \left (8 \, b^{2} d^{2} x^{2 \, n} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} - 4 \, {\left (2 \, \sqrt {b d} b d x^{n} + {\left (b c + a d\right )} \sqrt {b d}\right )} \sqrt {b x^{n} + a} \sqrt {d x^{n} + c} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x^{n}\right )}{4 \, {\left ({\left (b^{5} c d^{2} - a b^{4} d^{3}\right )} n x^{n} + {\left (a b^{4} c d^{2} - a^{2} b^{3} d^{3}\right )} n\right )}}, \frac {2 \, {\left (a b^{2} c d - 3 \, a^{2} b d^{2} + {\left (b^{3} c d - a b^{2} d^{2}\right )} x^{n}\right )} \sqrt {b x^{n} + a} \sqrt {d x^{n} + c} + {\left ({\left (b^{3} c^{2} + 2 \, a b^{2} c d - 3 \, a^{2} b d^{2}\right )} \sqrt {-b d} x^{n} + {\left (a b^{2} c^{2} + 2 \, a^{2} b c d - 3 \, a^{3} d^{2}\right )} \sqrt {-b d}\right )} \arctan \left (\frac {{\left (2 \, \sqrt {-b d} b d x^{n} + {\left (b c + a d\right )} \sqrt {-b d}\right )} \sqrt {b x^{n} + a} \sqrt {d x^{n} + c}}{2 \, {\left (b^{2} d^{2} x^{2 \, n} + a b c d + {\left (b^{2} c d + a b d^{2}\right )} x^{n}\right )}}\right )}{2 \, {\left ({\left (b^{5} c d^{2} - a b^{4} d^{3}\right )} n x^{n} + {\left (a b^{4} c d^{2} - a^{2} b^{3} d^{3}\right )} n\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{3 \, n - 1}}{{\left (b x^{n} + a\right )}^{\frac {3}{2}} \sqrt {d x^{n} + c}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{3 n -1}}{\left (b \,x^{n}+a \right )^{\frac {3}{2}} \sqrt {d \,x^{n}+c}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{3 \, n - 1}}{{\left (b x^{n} + a\right )}^{\frac {3}{2}} \sqrt {d x^{n} + c}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^{3\,n-1}}{{\left (a+b\,x^n\right )}^{3/2}\,\sqrt {c+d\,x^n}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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